A car accelerates uniformly from5ms-1 to 10ms-1 in 5sec calculate the a)
acceleration
b) the distance covered by the car at that time
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Answer:
u=5ms
v=10ms
t=5 sec .
a)a=v-u/t
=10-5/5
=5/5
=1ms^2
b)s=ut+1/2at^2
=5*5+1/2*1*5*5
=25+25/2
=37.5sec.
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