Question

A car accelerates uniformlyfrom 18 km h^–1

to 36km h^–1
in 5 sec. calculate–

i. Acceleration

ii. Distance covered by car​

Answer 1

Answer:

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Answer 2

Answer:

Given ,

t = 5 sec,

u = 18 km/hour,

$u = \frac{18 \times 1000}{60 \times 60s}$

u = 5m/s

v = 36km/hr

$v = \frac{36 \times 1000}{60 \times 60s}$

v = 10m/s

We know that,

a = (v-u)/t

substituting given values in the above equation we get,

a = (10-5)/5

a = 5/5

a = 1 ms^-1.

We know that distance travelled is calculated by the formula ↓

s = ut + 1/2 at ^2

substituting given values in the above equation we get,

s = 5×5+(1/2)×1×5^2

$s = 25 + 12.5$

$s = 37.5m$

Hence,

acceleration a = 1 m/s^2.

distance travelled s = 37.5 m.

Explanation:

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