a car accelerates unifromly from 18 km/h to 36 km/h in 5s calculate the acceleration
Answers
Answered by
1
Initial velocity = 18 km/h
= 18 * 5/18
=5m/s.
Final velocity= 36 km/h
= 36 * 5/18
= 10m/s.
Acceleration = v - u / t.
= 10 - 5 / 5
= 5/5
= 1 m/s^2
= 18 * 5/18
=5m/s.
Final velocity= 36 km/h
= 36 * 5/18
= 10m/s.
Acceleration = v - u / t.
= 10 - 5 / 5
= 5/5
= 1 m/s^2
mohak10:
thanks
Answered by
1
Answer:
Explanation:
Acceleration=(final velocity-initial velocity)/time.
So, a = (v-u) / t.
According to the question,
v=36km/h
u=18km/h
t= 5 s
=> v-u= 36 - 18 = 18;
=>a= 18/5 km/h
So, let us convert this ans into m/s
for that we can use this formula to convert km/h into m/s
i.e., to multiply by 5/18
so,18/5*5/18=1 m/s^-2
Here, 1 m/s is the ans because 18 and 5 gets cancelled .
(hope that this answer is useful to you and its error-free.if errors pls correct it.)
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