Question

a car accelerates with uniform rate from rest on a straight road the distance travelled in the last second of a 3 second interval from the start is 15 M then find the distance travelled in the first second in metre

Answer 1

The answer is in the image
Hope you are satisfied, the formula used is VERY IMPORTANT...

Answer 2

Answer:

The distance traveled in the first second is 3 m.

Explanation:

Given that,

The distance traveled in the last second of a 3 second interval from the start is 15 m.

We need to calculate the acceleration

For 3 second,

Using equation of motion

$S_{3}=ut+\dfrac{1}{2}a(2n-1)$

S = distance

a = acceleration

Put the value in the equation

$15=0+\dfrac{1}{2}a(2\times3-1)$

$a = \dfrac{15\times2}{5}$

$a=6\ m/s^2$

Now, The distance traveled in the first second

Using equation of motion again

$S_{1}=ut+\dfrac{1}{2}a(2n-1)$

$S_{1}=0+\dfrac{1}{2}\times6(2\times1-1)$

$S_{1}=3\ m$

Hence, The distance traveled in the first second is 3 m.