a car acceleration uniformly form 18 km/h to 36 km/h in 5 sec calculate (a) the acceleration (b) the distance covered by the car in that time
Answers
Answered by
1
Speed diff=18kmph=5mps
Acceleration= 5/5=1ms sq.
Distance=1m
Acceleration= 5/5=1ms sq.
Distance=1m
Answered by
6
u = 18×5/18=5
v= 36×5/18=10
acceleration= v-u/t
= 10-5/5
=5/5
=1m/sec^2
distance = s
s = ut + 1/2 at2
= 5 ×5 +1/2 × 1 (5)2
= 25 + 25 / 2
= 50+25/2
= 75/2
= 37.5 m....
hope this will help you
v= 36×5/18=10
acceleration= v-u/t
= 10-5/5
=5/5
=1m/sec^2
distance = s
s = ut + 1/2 at2
= 5 ×5 +1/2 × 1 (5)2
= 25 + 25 / 2
= 50+25/2
= 75/2
= 37.5 m....
hope this will help you
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