Question

A car acceleration uniformly from 18 kilometres per hour- 1 to 36 km per hour -1 in five seconds calculate the acceleration and distance covered by the car in the time

Answer 1

U=18km/h=18/60×1000/60=5m/s
V=36km/h=36/60×1000/60=10m/s
T=5s
Since,
V=u+at
:.10=5+5a
10-5=5a
5=5a
5/5=a
1m/s²=a
Now,
S=UT+1/2at²
S=5×5+1/2(25)
S=25+25/2
S=25+12.5
S=37.5m
(ÆÑẞWĒR)

Answer 2

Answer:

• Given parameters

Time taken (t) = 5 sec

Initial velocity (u) =18 km/hour

\(u = \frac{18\times 1000}{60\times 60s}\)

u = 5 m/s

Final velocity (v) =36km/hour

\(v = \frac{36\times 1000}{60\times 60s}\)

v =10 m/s

We need to calculate acceleration and distance traveled

We know that

acceleration a = (v – u)/t

Substituting the given values in the above equation we get,

a = (10 – 5)/5

a =5/5

a = 1 m/s2

We know that distance travelled is calculated by the formula

Distance travelled S = u t + (1/2) a × t2

Substituting the given values in the above equation we get,

S = 5 × 5 + (1/2) × 1 × 52

S = 25 + (1/2) × 25

S = 25 + 12.5

S = 37.5 m

Hence

acceleration a =1 m/s2

Distance travelled S =37.5 m