Question

a car acceleration uniformly from 18Km/h to 36km/h in 5 second calculate the acceleration of the car?​

Answer 1

given :-

initial velocity = u = 18km/h

final velocity = v = 36km/h

time = t = 5 seconds

time is in seconds, so first of all, we've to convert velocities in m/s

for that, we can multiply both the velocities by 5/18

➡ u = 18 × 5/18 = 5m/s

➡ v = 36 × 5/18 = 2 × 5 = 10m/s

now using first equation of motion that is, v = u + at

just put the values of u, v and t.

➡ 10m/s = 5 + 5a

➡ 10 - 5 = 5a

➡ 5 = 5a

➡ a = 5/5

➡ a = 1m/s²

hence, the acceleration of the car is 1m/s²

Answer 2

» A car acceleration uniformly from 18Km/h to 36km/h in 5 second.

Here..

• Initial velocity (u) = 18 km/hr

=> 18 × $\frac{5}{18}$

=> 5 m/s

• Final velocity (v) = 36 km/hr

=> 36 × $\frac{5}{18}$

=> 2 × 5

=> 10 m/s

• Time (t) = 5sec

________________ [GIVEN]

• We have to find the acceleration (a) of the car.

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We know that..

$\boxed{*\:v\:=\:u\:+\:at}$

(From first equation of motion)

Put the known values in above formula..

=> 10 = 5 + 5a

=> 10 - 5 = 5a

=> 5 = 5a

=> a = ${ \dfrac{ \cancel{5}}{ \cancel{5}} }^{1}$

=> a = 1 m/s²

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Acceleration of the car is 1 m/s².

____________ [ANSWER]

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