a car accerate uniform by from 20 km/h to 40km/ h in 5sec.calculate the acceleration and distance covered by car in that time
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v=40*5/18=100/9
u=20*5/18=50/9
t =5
a=v-u/t
100-50/9*5=10/9
distance (s) = 2as = v^2-u^2
2(10/9)s=(100/9)^2-(50/9)^2
20/9s=7500
s=31500
8s=1200
s=1200/8
u=20*5/18=50/9
t =5
a=v-u/t
100-50/9*5=10/9
distance (s) = 2as = v^2-u^2
2(10/9)s=(100/9)^2-(50/9)^2
20/9s=7500
s=31500
8s=1200
s=1200/8
Akriti111:
Hope you get your answer
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