Physics, asked by pkour3402, 6 months ago

A car accerlates from 6metre sec1 in 10sec calculate the accerlation and the distance covered by the car in that time

Answers

Answered by Anonymous
56

Solution :—

Given :-

  • Initial Velocity (u) = 6 m/s
  • Final Velocity (v) = 0 m/s
  • Time Taken (t) = 10 a

To Find :-

  • Acceleration (a)
  • Distance Travelled (s)

Calculating Acceleration

Formula Used :-

  • v = u + at

⟹ 0 = 6 + a × 10

⟹ 0 = 6 + 10a

⟹ -6 = 10a

⟹ 10a = -6

⟹ a = -6/10

⟹ a = -0.6

Thus, acceleration is -0.6 m/s²

Note :- If there is a negative sign it denotes that there is a negative acceleration i.e retardation

Calculating Distance Covered

Formula Used :-

  • v² - u² = 2as

⟹ (0)² - (6)² = 2 × -0.6 × s

⟹ 0 - 36 = -1.2 s

⟹ 1.2 s = 36

⟹ s = 30

Thus, Distance Covered is 30 m

Hence, Solved

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