A car accerlates from 6metre sec1 in 10sec calculate the accerlation and the distance covered by the car in that time
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Solution :—
Given :-
- Initial Velocity (u) = 6 m/s
- Final Velocity (v) = 0 m/s
- Time Taken (t) = 10 a
To Find :-
- Acceleration (a)
- Distance Travelled (s)
Calculating Acceleration
Formula Used :-
- v = u + at
⟹ 0 = 6 + a × 10
⟹ 0 = 6 + 10a
⟹ -6 = 10a
⟹ 10a = -6
⟹ a = -6/10
⟹ a = -0.6
Thus, acceleration is -0.6 m/s²
Note :- If there is a negative sign it denotes that there is a negative acceleration i.e retardation
Calculating Distance Covered
Formula Used :-
- v² - u² = 2as
⟹ (0)² - (6)² = 2 × -0.6 × s
⟹ 0 - 36 = -1.2 s
⟹ 1.2 s = 36
⟹ s = 30
Thus, Distance Covered is 30 m
Hence, Solved ♡
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