A car accquires a velocity of 40 km/h in 30 sec just after the start. calculate the acceleration of the car.
Answers
Answered by
1
Heya!!
--------------------------
Given :
u(initial velocity) = 0 m/s
v(final velocity) = 40km/h
= 40 * 1000 / 60*60 m/s
= 200/18 m/s
= 100/9 m/s
t(time interval) = 30 s
To find : a(acceleration)
Since a = (v-u) /t
= (100/9 - 0) / 30
= 100/9 / 30 m/s^2
= 100/270 m/s^2
= 10/27 m/s^2
Or
0.37.. m/s^2 °
Hope it helps u :)
--------------------------
Given :
u(initial velocity) = 0 m/s
v(final velocity) = 40km/h
= 40 * 1000 / 60*60 m/s
= 200/18 m/s
= 100/9 m/s
t(time interval) = 30 s
To find : a(acceleration)
Since a = (v-u) /t
= (100/9 - 0) / 30
= 100/9 / 30 m/s^2
= 100/270 m/s^2
= 10/27 m/s^2
Or
0.37.. m/s^2 °
Hope it helps u :)
Answered by
0
v=forty km/hr
=forty*5/18=11.11
u=0
time=30 sec
therefore acc:
by using i eq. of motion
40=a*30
40/30=a
4/3=a
a=1.33m^2
=forty*5/18=11.11
u=0
time=30 sec
therefore acc:
by using i eq. of motion
40=a*30
40/30=a
4/3=a
a=1.33m^2
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