Question

A car accumilates from rest to a speed 29m/s in 50 sec what s accumulation of car in m/s2

Answer 1

Answer:

0.58 m/s²

Explanation:

Given :

• Initial velocity of the car = 0 m/s = u

• Final velocity of the car = 29 m/s = v

• Time taken = 50 seconds = t

To find :

• Acceleration of the car in the given time period

$acceleration \: = \frac{v - u}{t}$

Where:

V = final velocity

u = Initial velocity

t = time

Substituting the values :

Acceleration = (29-0)/50

Acceleration = 29/50

Acceleration = 0.58 m/s²

The acceleration of the car in the given time period is equal to 0.58 m/s²

Answer 2

Answer:

Given:

• A car accumulates from rest to a speed 29m/s in 50 sec.

Find:

• What is acceleration of the car in m/s².

Using formula:

${\sf{\underline{\boxed{\green{\sf{ Acceleration = \dfrac{(Final \: velocity - Initial \: velocity) }{Time}}}}}}}$

Know terms:

1. Initial velocity = (u)
2. Final velocity = (v)
3. Time = (t)
4. Acceleration = (A)

Adding values, we get:

⇒ $\sf A = \dfrac{(29-0)}{50}$

⇒ $\sf A = \dfrac{29}{50}$

⇒ ${\sf{\underline{\boxed{\green{\sf{A = 0.58 \: m/s^2}}}}}}$

Therefore, 0.58 m/s² is the acceleration of the car.