Question

a car accurs a speed of 36km/hr in 20 sec starting from rest calculate the accelation of the car​

Answer 1

Answer:

$\boxed{\mathfrak{Acceleration \ (a) = 0.5 \ m/s^2}}$

Given:

Initial velocity (u) = 0 km/h = 0 m/s

Final velocity (v) = 36 km/h = 10 m/s

Time taken (t) = 20s

To Find:

Acceleration (a) of the car

Explanation:

★ Converting km/h to m/s:

$\sf 1 \: km/h = \frac{5}{18} m/s$

So,

$\sf Final \: velocity \: (v) = 36 \: km/h \\ \\ \sf = 36 \times \frac{5}{18} \: m/s \\ \\ \sf = 2 \times 5 \: m/s \\ \\ \sf = 10 \: m/s$

$\star \ \sf From \: 1^{st} \: equation \: of \: motion: \\ \boxed{ \bold{ v = u + at}}$

Substituting value of v, u & t in the equation:

$\sf \implies 10 = 0 + a(20) \\ \\ \sf \implies 20a = 10 \\ \\ \sf \implies a = \frac{10}{20} \\ \\ \sf \implies a = 0.5 \: m {s}^{ - 2}$

$\therefore$

Acceleration (a) of the car = 0.5 m/s²

Answer 2

Answer:

v = 36 km/h = 10 m/s

u = 0 m/s

t = 20 s

v = u + at

10 = 0 + 20a

a = 10/20

a = 0.5 m/s²