Question

A car acquires a velocity of 180km/h in 20 sec starting from rest find a acceleration,avrage velocity, distance travelled in this time.

Answer 1

Hey user,
v = 180km/hr= 180×5/18=50m/s
u= 0
t = 20secs

(1) a = v-u/t
a= 50-0/20
a= 50/20
a=5/2
a= 2.5 m/s^2

(2) average velocity=
total displacement/ total time
= 50/20
=5/2=2.5m/s

(3) s = ut+1/2*at^2
= (0)(20) + 1/2* (2.5)(20)^2
= 0+ 2.5/2×400
=2.5×200
= 500m
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Answer 2

Answer:

Given

v=180km/hr 180×5÷18=50m/s

u=0

t=20s

Explanation:

a=v-u

t

a=50-0/20

a=2.5m/s²

av velocity = 50/20=2.5m/s

by eq of motion

s=ut+1/2at²

s= 0×20+1/2×2.5×20²

s=2.5×200

s=500

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