Question

A car acquires a velocity of 36 Km/h in 10s starting from rest . Calculate :(i) the acceleration.(ii) the average velocity and (iii) the distance travelled in this time.

Answer 1

Given:-

→Initial velocity of the car = 0

(as it starts from rest)

→Final velocity of the car = 36km/h

→Time taken = 10s

To find:-

Firstly, let's convert the final velocity of the car from km/h to m/s.

=>1km/h = 5/18m/s

=>36km/h = 5/18×36

=>10m/s

By using the 1st equation of motion,we get:-

=>v = u+at

=>a = v-u/t

=>a = 10-0/10

=>a = 1m/s²

When a body is moving with uniform acceleration,then average velocity of the body is:-

=>Vₐᵥ = u+v/2

=>Vₐᵥ = 0+10/2

=>Vₐᵥ = 5m/s

Now,by using the 2nd equation of motion,we get:-

=>s = ut+1/2at²

=>s = 0(t) + 1/2×1×(10)²

=>s = 0.5(100)

=>s = 50m

Thus:-

→Acceleration of the car is 1m/s².

→Average velocity of the car is 5m/s.

→Distance travelled by the car is 50m.