A car acquires a velocity of 72 km/h in 10 sec starting from rest find (i) acceleration (ii) average velocity (iii)distance travelled
Answers
Answered by
5
v = 72 km/h = 20 m/s
t = 10s
u = 0 km/h = 0 m/a
a = (v-u)/t
= 20/10 = 2 m/s²
avg. velocity (v+u)/2
= 20/2 = 10 m/s
s = ut + ½at²
= 0×10 + ½ × 2 × 100
= 50 m
t = 10s
u = 0 km/h = 0 m/a
a = (v-u)/t
= 20/10 = 2 m/s²
avg. velocity (v+u)/2
= 20/2 = 10 m/s
s = ut + ½at²
= 0×10 + ½ × 2 × 100
= 50 m
anil172:
distance is 50m
i wrote that
Answered by
5
v = 72 km/h = 20 m/s
t = 10s
u = 0 km/h = 0 m/a
a = (v-u)/t
= 20/10 = 2 m/s²
avg. velocity (v+u)/2
= 20/2 = 10 m/s
s = ut + ½at²
= 0×10 + ½ × 2 × 100
= 50 m
t = 10s
u = 0 km/h = 0 m/a
a = (v-u)/t
= 20/10 = 2 m/s²
avg. velocity (v+u)/2
= 20/2 = 10 m/s
s = ut + ½at²
= 0×10 + ½ × 2 × 100
= 50 m
Similar questions