Question

A car acquires a velocity of 72 km/h in 10 sec starting from rest find (i) acceleration (ii) average velocity (iii)distance travelled

Answer 1

v = 72 km/h = 20 m/s
t = 10s
u = 0 km/h = 0 m/a

a = (v-u)/t
= 20/10 = 2 m/s²

avg. velocity (v+u)/2
= 20/2 = 10 m/s

s = ut + ½at²
= 0×10 + ½ × 2 × 100
= 50 m

Answer 2

v = 72 km/h = 20 m/s
t = 10s
u = 0 km/h = 0 m/a

a = (v-u)/t
= 20/10 = 2 m/s²

avg. velocity (v+u)/2
= 20/2 = 10 m/s

s = ut + ½at²
= 0×10 + ½ × 2 × 100
= 50 m