A car acquires a velocity of 72 km /h in 10seconds starting from the rest.
find (a) the acceleration (b) the average speed (c) the distance travelled in this time.
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Answers
→ Hey User,
→ Given Question:-
→ A car acquires a velocity of 72 km /h in 10seconds starting from the rest. find (a) the acceleration (b) the average speed (c) the distance travelled in this time.
→ To find:-
→ (a) the acceleration
→ (b) the average speed
→ (c) the distance traveled in this time
→ Answer:-
→ u = 0km/h
→ v = 72km/h
→ t = 10s
→ v = u + at
→ 72 km / h = a ( 10 )s
→ 72 × 5 / 18 × 1 / 10 = a
→ a = 2m/s²
→ (a) so , the acceleration is 2m/s².
→ Now,
→ v² - u² = 2as
→ ( 72 × 5 / 18 ) =
→ 2 × 2 × 5
→ s = 1 /4 ( 400) =
→ 100m
→ vav = 100m/10s
→ = 10m/s
→ (b) so, the average speed is 10m/s.
→ (c) so , the distance travelled in this time is :
→ s = 1/4 ( 400 ) = 100m
→ 100m
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Answer:
→ Hey Mate : )
→ Given Question:-
→ A car acquires a velocity of 72 km /h in 10seconds starting from the rest. find (a) the acceleration (b) the average speed (c) the distance travelled in this time.
→ To find:-
→ (a) the acceleration
→ (b) the average speed
→ (c) the distance traveled in this time
→ Answer:-
→ u = 0km/h
→ v = 72km/h
→ t = 10s
→ v = u + at
→ 72 km / h = a ( 10 )s
→ 72 × 5 / 18 × 1 / 10 = a
→ a = 2m/s²
→ (a) so , the acceleration is 2m/s².
→ Now,
→ v² - u² = 2as
→ ( 72 × 5 / 18 ) =
→ 2 × 2 × 5
→ s = 1 /4 ( 400) =
→ 100m
→ vav = 100m/10s
→ = 10m/s
→ (b) so, the average speed is 10m/s.
→ (c) so , the distance travelled in this time is :
→ s = 1/4 ( 400 ) = 100m
→ 100m
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