Question

A car acquires a velocity of 72 km/hr in 10 seconds starting from rest. Find (a) the acceleration (b) the average velocity, and (c) the distance travelled in this time.

Answer 1

72 km\ph = 72 *5/18 = 20 m/s

apply v = u+at

20 = 10a

a = 2 m/s^2

distance = V^2 -U^2 =2as

20^2 = 2[2}{s}

400 = 4s

s =100 meters

average velocity = displacement / time = 100 /10 = 10 m/s

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Answer 2

acceleration is = v/t
change 72 into meter per sec
72
$(72 \times 5) \div 18 = 20$
then 20/10=2 mtr/sec2
average velocity will be same 20
distance traveled= v^2/2a
20^20/2*2 = 100mtr