Question

a car acquires a velocity of 72 km/hr in 5 minutes starting from rest. Find acceleration,the average velocity
,the distance travelled in this time

Answer 1

u = 0
v = 72 km/h = 72 × 5/18 = 20 m/s
t = 5 mins = ( 5×60 ) = 300 s



a = v- u/ t
= 20-0 / 300
= 20/300
= 1/15
= 0.06666..... metre per second square




Average velocity = v + u / 2
= 20 + 0 / 2
= 10 m/s






$s \: = \: ut \: + \: 1 \div 2 \: a {t}^{2}$
= 0×300 + 1/2 × 1/15 × 300 × 300
= 300 × 10
= 3000 m




I m sorry if I m wrong. :)