Question

A car acquires a velocity of 72 km per hour in 10 seconds starting from rest.find(i) the acceleration,(ii)the average velocity,(iii) the distance travelled in this time?

Answer 1

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հίί ʍαtε_______✯◡✯
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һєяє' ʏȏȗя ѧṅśwєя ʟȏȏҡıṅɢ ғȏя________
.
✯●given that ,

❶♦ car is traveling at 72 kph = 72 / hour ( 1 hr / 3600sec)
1000m / km = 20m / sec

then, using the formula

=》
$a = \frac{vf - vi } {t} = \frac{20 - 0}{10} = 2 \: m {s}^{2}$

▶♦ the average acceleration is is 2 m/ s^2.
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❷♦the average velocity is ,

$v = \frac{vf + vi}{2} = \frac{20 + 0}{2} = 10 \: m {s}^{2}$
▶the average velocity is 10 m/s^2.
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❸♦Distance traveled at constant acceleration is,

=》
$d = ( \frac{1}{2} ).a {t}^{2}$
=》
$( \frac{1}{2} ).(2).(10 {)}^{2} = 100m$

▶the car traveled 100m.
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$hope \: it \: helps$


★★BRAINLY★★

Answer 2

✯●given that ,

❶♦ car is traveling at 72 kph = 72 / hour ( 1 hr / 3600sec)

1000m / km = 20m / sec

then, using the formula

=》

a = \frac{vf - vi } {t} = \frac{20 - 0}{10} = 2 \: m {s}^{2}a=

t

vf−vi

=

10

20−0

=2ms

2

▶♦ the average acceleration is is 2 m/ s^2.

___________________________

❷♦the average velocity is ,

v = \frac{vf + vi}{2} = \frac{20 + 0}{2} = 10 \: m {s}^{2}v=

2

vf+vi

=

2

20+0

=10ms

2

▶the average velocity is 10 m/s^2.

_________________________

❸♦Distance traveled at constant acceleration is,

=》

d = ( \frac{1}{2} ).a {t}^{2}d=(

2

1

).at

2

=》

( \frac{1}{2} ).(2).(10 {)}^{2} = 100m(

2

1

).(2).(10)

2

=100m

▶the car traveled 100m