A car acquires a velocity of 72 km per hour in 10 seconds starting from rest.find(i) the acceleration,(ii)the average velocity,(iii) the distance travelled in this time?
Answers
Answered by
18
★★
հίί ʍαtε_______✯◡✯
.
.
.
.
_________________________
һєяє' ʏȏȗя ѧṅśwєя ʟȏȏҡıṅɢ ғȏя________
.
✯●given that ,
❶♦ car is traveling at 72 kph = 72 / hour ( 1 hr / 3600sec)
1000m / km = 20m / sec
then, using the formula
=》
▶♦ the average acceleration is is 2 m/ s^2.
___________________________
❷♦the average velocity is ,
▶the average velocity is 10 m/s^2.
_________________________
❸♦Distance traveled at constant acceleration is,
=》
=》
▶the car traveled 100m.
__________★★
★★BRAINLY★★
հίί ʍαtε_______✯◡✯
.
.
.
.
_________________________
һєяє' ʏȏȗя ѧṅśwєя ʟȏȏҡıṅɢ ғȏя________
.
✯●given that ,
❶♦ car is traveling at 72 kph = 72 / hour ( 1 hr / 3600sec)
1000m / km = 20m / sec
then, using the formula
=》
▶♦ the average acceleration is is 2 m/ s^2.
___________________________
❷♦the average velocity is ,
▶the average velocity is 10 m/s^2.
_________________________
❸♦Distance traveled at constant acceleration is,
=》
=》
▶the car traveled 100m.
__________★★
★★BRAINLY★★
khushi12345610:
hello dear :-D
Answered by
1
✯●given that ,
❶♦ car is traveling at 72 kph = 72 / hour ( 1 hr / 3600sec)
1000m / km = 20m / sec
then, using the formula
=》
a = \frac{vf - vi } {t} = \frac{20 - 0}{10} = 2 \: m {s}^{2}a=
t
vf−vi
=
10
20−0
=2ms
2
▶♦ the average acceleration is is 2 m/ s^2.
___________________________
❷♦the average velocity is ,
v = \frac{vf + vi}{2} = \frac{20 + 0}{2} = 10 \: m {s}^{2}v=
2
vf+vi
=
2
20+0
=10ms
2
▶the average velocity is 10 m/s^2.
_________________________
❸♦Distance traveled at constant acceleration is,
=》
d = ( \frac{1}{2} ).a {t}^{2}d=(
2
1
).at
2
=》
( \frac{1}{2} ).(2).(10 {)}^{2} = 100m(
2
1
).(2).(10)
2
=100m
▶the car traveled 100m
Similar questions