Question

A car acquires a velocity of 72 km per hour in 10 seconds starting from rest. Find
(i) The acceleration,
(ii) The average velocity
(iii) Distance traveled in this time.
seconds.

Answer 1

Answer:

Given:

u is the initial velocity = 0 m/s

v is the final velocity = 36 Km/hr = 36 x (1000/3600)=10 m/s

t is the time period = 10 ×60 =600 s

a = 2 m/s2

avg. velocity=

formula used:1. final velocity " V "= u + a × twhere ,v is the final velocityu is the initial velocitya is the acceleration of the bodyt is the time period2. Using third equation of motionv2 - u2 =2 × a × s

where,v is the final velocityu is the initial velocitya is the accelerations is the displacementputting the value of v,u,t in equation 110 =0 +a × 600a = 0.0167 ms-2

putting the value of v,u,a,t in equation 2100-0=2×0.0167×ss =3000 m= 3 km

The average velocity is 5 m/s , acceleration is 0.0167 ms-2, displacement is 3 km