Question

A car acquires a velocity of 90kmph in 10 second starting from rest.The distance travelled during this period is____________. *

125 m
100 m
125 km
100 km

Answer 1

Answer:

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Answer 2

Answer:

125 m

Explanation:

Here,

u= 0 m/s

v= 90 km/h = (90 x 5/18) m/s = 25 m/s.

t= 10s.

a=( v-u) /t =( 25 - 0)/ 10= 25/10 = 2.5 m/s^2.

Distance = ut+0.5at^2 = 0 x 10 + 0.5 x 2.5 x 10 x 10

= 0 + 5 x 25 = 125m