Physics, asked by yuria, 1 year ago

a car aequires a velocity of 72 km/h in 20 sec starting from the rest find the distance covered by this time

Answers

Answered by Tamash
4
72kmph=20m/s

hence acceleration= (v-u)/t
=(20-0)/20
=1m/s²

travelled distance= u*t. + ½at²
=0+½*1*20*20
=. 200meter
Answered by Ramsam
0
pls mark as brainlist
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