A car after traveling 18 km from a point A developed some problem in the engine and
speed became 4/5 of its original speed. As a result, the car reached point B 45 minutes
late. If the engine had developed the same problem after traveling 30 km from A, then it
would have reached B only 36 minutes late. The original speed of the car (in km per
hour) and the distance between the points A and B (in km.) are
(CAT 90)
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He proceeds at 45
S where S is his usual speed means 15
decrease in speed which will lead to 14
increase in time.
Now the main difference comes in those 12km (30 - 18) and the change in difference of time = (45 - 36) min = 9 min
Thus,
14
× T = 9 min where T is the time required to cover the distance of (30 - 18) = 12 km
T = 36 min = 3660
hours = 0.6 hours.
Speed of the car = 120.6
= 20 kmph.
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