Question

A car applies brakes and decelerates from 82m/s to 61 m/s in 0.90s.Calculate its deceleration​

Answer 1

Answer:

23.33 m/s²

Explanation:

Given:

Initial velocity (u) = 82 m/s

Final velocity (v) = 61 m/s

Time (t) = 0.9 seconds

To find:

Deceleration, i.e, negative acceleration (a)

Method to find:

a = (v-u)/t

⇒ a = (61-82)/0.9

⇒ a = -21/0.9

⇒ a = -23.3333333333 m/s² ≈ -23.33 m/s²

Since deceleration is a negative acceleration, it will be -(-23.33) m/s², which is 23.33 m/s².

Hence, the deceleration of the car is 23.33 m/s².