Question

"A car applies brakes to stop the car with an acceleration of 5 m/s^ in 5s, calculate the velocity of moving
car and also find the distance after which car stops​

Answer 1

Answer:

answer is..

Explanation:

a= 5m/sec square

t = 5sec

v= 0

v= u+at

0= u+5*5

u=25m/sec

s=ut+1/2 at square

= 25 *5 +1/2 *5*5 square

125 + 1/2 * 125

125+62.5

75 meter

hope it helps you

Answer 2

Answer:

Initial velocity = 25m/s

Distance = 137.5m

Explanation:

Given -

• Final velocity (v) =0m/s
• Acceleration (a) = - 5m/s² (retardation)
• Time (t) =5 seconds.

Solution -

Initial velocity (u) -

• v=u+at
• 0=u+(-25)
• 25=u

Initial velocity is 25m/s

Distance (s) -

• ut+1/2at²
• (25×5)+1/2(5)(5)
• 125+ 25/2
• 125+12.5
• 137.5 m

Distance travelled is 137.5m