Question

a car approaches a stop going 5m/s before it comes to a stop. if it does this in 4 seconds, what was its acceleration?

Answer 1

Answer:

Hii mate!

We'll proceed using the equation of motion:

v=u-at (as here deceleration is into action that means negative acceleration)

here,

v=0

u=5m/s

t=4sec

a=?

0=5-4a

4a=5

a=5/4

a=1.25m/s^2

I hope it helped you.

If you have any further doubt, feel free to ask.