A car aquires a velocity of 72km/h in 10/sec starting from rest.find (a) acceleration,(b) average velocity,(c) distance travelled in time
Answers
Answered by
2
HEYA!!
---------
We are Given that ,
Initial velocity u = 0
Final velocity v= 72 km/hr
= 72 × 5/18. = 20 m/s.
Time t = 10 seconds
⏪Acceleration :
V= U + AT. [ first equation of motion ]
0 + 10 A = 20
A = 2ms-2 .
⏪distance travelled S =
S = Ut + 1/2 AT^2
[Second Equation of Motion ]
S = 1/2 × 2 × (10)^2
S = 100 m
⏪Average Velocity = 100/10
= 10 m/s
----------------------------------------------------------------------------------------------------
---------
We are Given that ,
Initial velocity u = 0
Final velocity v= 72 km/hr
= 72 × 5/18. = 20 m/s.
Time t = 10 seconds
⏪Acceleration :
V= U + AT. [ first equation of motion ]
0 + 10 A = 20
A = 2ms-2 .
⏪distance travelled S =
S = Ut + 1/2 AT^2
[Second Equation of Motion ]
S = 1/2 × 2 × (10)^2
S = 100 m
⏪Average Velocity = 100/10
= 10 m/s
----------------------------------------------------------------------------------------------------
Similar questions