Question

a car at rest accelerate uniformly to speed of 40ms-1 n 20s . how much distance is covered by the car

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Answer 1

$\sf \pink{ \tt{Answer:-}}$

$\sf \green{ \tt{Given:-}} \\ </p><p>{\tt {u = 0 }}\\ { \tt{v = 40m/s}} \\{ \tt{t = 20 \: s}}$

$\sf \red{ \tt{we \: know}} \\{ \tt{ \implies \: v = u + at}} \\ { \tt{ \implies \: 40 = a \times 20}} \\ {\tt{\implies \: a = 2m/s²}}$

$\sf \blue{ \tt{now}} \\{ \tt{ \implies \: s = ut + \frac{1}{2} a {t }^{2} }}\\ { \tt{\implies \: s = \frac{1}{2} a {t}^{2} }} \\ { \implies \: \frac{1}{2} \times 2 \times 2 {0}^{2} } \\ { \tt{ \implies \: s = 400m}}$

Thanks

Answer 2

Answer:

Explanation:

Given,

• Initial velocity, u = 0 m/s
• Final velocity, v = 40 m/s
• Time taken, t = 20 seconds

To Find,

• Distance covered, s = ?

Formula to be used,

• Acceleration formula, a = v - u/t
• 3rd equation of motion, v² - u² = 2as

Solution,

At first, we will find acceleration,

Acceleration, a = (v - u)/t

⇒ Acceleration formula, a = (v - u)/t

⇒ a = (40 - 0)/20

⇒ a = 40/20

⇒ a = 2 m/s²

Here, accelration is 2 m/s².

Now, the distance covered y car,

v² - u² = 2as

⇒ (40)² - (0)² = 2 × 2 × s

⇒ 1600 = 4s

⇒ s = 1600/4

⇒ s = 400 m

Hence, the distance covered by car is 400m.