A car at rest accelerates uniformly to a speed of 144km/hr in 20 sec how much distance covered by the car
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Answer:
Explanation:
Given :-
Final Velocity of a car, v = 144 km/h = 5/18 × 144 = 40m/s
Initial Velocity of a car, u = 0
Time taken by car, t = 20 seconds
To Find :-
Distance is covered by the car.
Formula to be used :-
Newton's 1st equation i.e v = u + at
Newton's 2nd equation i.e s = ut + 1/2 at²
Solution :-
Putting all values, we get
⇒ v = u + at
⇒ 40 = 0 + 20 × a
⇒ a = 2 m/s²
Putting acceleration value on 2nd equation
⇒ S = ut + 1/2 at²
⇒ S = 1/2 x 2 x (20)²
⇒ S = 400 m
Hence, the distance is covered by the car is 400 m.
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