Question

a car at rest speeds up to 4m/s². what will be its speed after 0.1sec​

Answer 1

Answer:

0.4m/s

Explanation:

initial velocity =u=0m/s

acceleration =4m/s²

final velocity =v

time =0.1s

v=u+at (first equation of motion )

v=0+4×0.1

v=0.4m/s

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Answer 2

Answer:

speed is 0.4m/s  

Explanation:

given-

        acceleration (a)= $4m/s^2$

        initial velocity (u)= 0 m/s

        time (t)= 0.1 sec

using first equation of motion i.e.,   $v=u-at$

                                                          = $v=0+(4*0.1)\\v=0+0.4\\v=0.4m/s$