Question

a car attains a velocity of 36km/hr after accelarating uniformly from rest in 5 seconds.Find the distance travelled​

Answer 1

GIVEN:

Initial velocity = 0

Final velocity = 36 km/h

Time taken = 5 second

TO FIND :

distance travelled

FORMULA USED:

• v = u+at
• s = ut+1/2 at²

where :-

V = Final velocity

U = Initial velocity

a = acceleration

t = time taken

s = distance travelled

SOLUTION :

First we will convert 36km/h in m/s :-

1km = 1000 m

1 hour = 3600 seconds

$⟹36km/h = \frac{36 \times 1000}{3600} \: \frac{m}{s}$

$⟹36km/h = \frac{36000}{3600} \: \frac{m}{s}$

$⟹36km/h = 10 \: \frac{m}{s}$

To find acceleration use the given Formula :-V = U + at

put :-

Initial velocity ( U) = 0

Final velocity (V) = 10m/s

Time taken (t) = 5 second

⟹10 = 0 + 5a

⟹10/5 = a

⟹2 m/s² = a

Acceleration = 2m/s²

To find distance use the given Formula :-

s = ut+1/2 at²

put

• u = 0
• t = 5
• a = 2

⟹s = 0 +(1/2 ×2 × 5²)

⟹s = 25

ANSWER :

distance travelled = 25 m

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More Formulae :-

1. v = u+at

2. v²-u²= 2as

3. s = ut+1/2 at²

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