A car battery of 12 v is connected in series with resistor of 0.1 ohm , 0.2 ohm , 0.2 ohm , 0.4 ohm and 6 ohm. How much current would flow through 6 ohm resistor
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Answer:
Explanation:
Since all resistances are connected in series then
Rnet=0.1+0.2+0.2+0.4+6=6.9ohm
I =V/Rnet
=120/69
=1.7391ohms
Therefore that same current will slow through entire circuit and in every resistance
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