Question

A car battery of emf 12 v and internal resistance 5 × 10−2 ω, receives a current of 60 amp, from external source, then terminal potential difference of battery is

Answer 1

where, E=12 v ,r=5 × 10−2 ω,I=60 amp...V=?
solution :
V=E-Ir
V=12-(60x5x10-2)
V=12-3
V=9v