A car brakes from a speed of 108km/h to 72km/h during a displacement of 100m. What is its acceleration?
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Heya!!
Thanks for asking the question!
Here is your answer :-
Given ,
u = 108 km/hr = 30m/s
v= 72 km/hr = 20m/s
s= 100m
a= ?
We can use third equation of motion to determine a since a is only unknown to us.
v^2=u^2+2as
Substituting the values:
(20)(20)=(30)(30)+2(a)(100)
400 = 900 + 200a
200a = -500
a = -500/200
a = -2.5m/s^2. (Ans)
Hope it helps you.
Thanks for asking the question!
Here is your answer :-
Given ,
u = 108 km/hr = 30m/s
v= 72 km/hr = 20m/s
s= 100m
a= ?
We can use third equation of motion to determine a since a is only unknown to us.
v^2=u^2+2as
Substituting the values:
(20)(20)=(30)(30)+2(a)(100)
400 = 900 + 200a
200a = -500
a = -500/200
a = -2.5m/s^2. (Ans)
Hope it helps you.
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