Question

A car came to rest when break was applied for 4 seconds to get a retardation of 3m/s square. Calculate how far the car would have travelled after applying the break.?​

Answer 1

Answer:

24 m

Explanation:

t= 4s

a= -3m/s sqrt

s=?

v=0

v=u+at

u=v-at

= 0-(-3)×4

=12 m/s

s=ut+1/2at^2

=12 ×4+ 1/2 (-3)×4×4

=48-24

=24 m

Answer 2

Explanation:

time=. 4second

a= 3metre/ second square

s= not given

v=u+at u=v-at

that = o- (-3×4)=12metre/second

s=ut+1

2at^2

12×4+1/2(-3)×16

48-24

24metre