Question

A car came to rest when break was applied for 4 seconds to get a retardation of 3m/s square. Calculate how far the car would have travelled after applying the break.?​

Answer 1

Answer:

t= 4s

a= -3m/s sqrt

s=?

v=0

v=u+at

u=v-at

= 0-(-3)×4

=12 m/s

s=ut+1/2at^2

=12 ×4+ 1/2 (-3)×4×4

=48-24

=24 m

Answer 2

Answer:

24m/s

Explanation:

t=4

a=-3m/s²

s=?

v=u+at

u=v-at

=0-(-3)×4

=12m/s

s=ut+1/2(at)²

=12×4+1/2(-3)×4×4

=48-24

=24