Question

A car can cover a distance in 4 hour at speed 60 kmph then by what percent should the speed

of car be increased to cover the same distance in 2.5 hr​

Answer 1

Answer:

so, the speed of the car should be increase by 60% to cover the same distance in 2.5hours

Step-by-step explanation:

speed of the car = 60 kmph

time taken to cover the distance = 4hours

=> distance covered =  speed * time = 60*4 km

                                                            = 240km

time expected to cover 240km = 2.5hours

so, the speed = distance / time

                       = 240km / 2.5 hour

                       = (240/2.5)*(4/4) kmph

                       = (240*4) / (2.5*4) kmph

                       = 960 / 10 kmph

                       = 96 kmph

so, the difference in speed = (96-60) kmph

                                             = 36 kmph

for 60 kmph , the increment is 36kmph

so, for 100kmph, the increment =  (100*36)/60 %

                                                     = (100*36)/(6*10) %

                                                     = (10*6) %

                                                     = 60 %

Answer 2

Answer:

The speed of the car must be increased by 60%

Step-by-step explanation:

Given that,

A car can cover a certain distance in 4 hours at a speed of $V_{1}=60km/h$

We are required to find the percentage by which the speed of car must be increased to cover the same distance in 2.5 hours.

As we know that Speed is the ratio of distance traveled to the time,for first case we shall use

$60=\frac{Distance}{4} = > Distance=60\times4=240km$

Hence the distance covered in a time period of 4 hours is 240km.

Now to cover this distance in 2.5hours,our speed is calculated as shown below

$V_{2}=\frac{240km}{2.5hr} =96km/h$

Now the percentage increase in speed is calculated by the relation

$\frac{V_{2}-V_{1}}{V_{1}} \times100$

Substituting the values of speed we get the increase in percentage as

$\frac{96-60}{60} \times100=60\%$

Therefore,the speed of the car must be increased by 60%

#SPJ3