Question

A car celebrates uniformly from 20km/h in 5s. Calculate-
1. Acceleration
2. The distance covered by car in that time

Answer 1

acceleration= 100ms

distance =4,ms

Answer 2

V=20km/hr=5.5m/s

T=5s

1) v=ut+at

=5.5=0+5a

=a=5.5/5

=a=1.1m/s²

or a= 1m/s²

2)S=ut+1/2at²

=s=0+1/2*1*(5)²

=s=1/2*25

=s=12.5m

or s=12.5/1000km

=0.0125km

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