Question

A car changes its velocity 18km/hr to 36km/hr in 1min calculate the distance travelled by the car within this time

Answer 1

u = 18km/h = 5m/s
v = 36km/h = 10m/s
time = 60s
a = 0.083m/s²
2as = v² - u²
2×0.083×s = 100 - 25
s = 451.8m

Answer 2

Hello mate!!


Acceleration = Change in Velocity/Time 

Change in Velocity = 36-18 = 18 km/h=5 m/s 
Time= 5 Seconds 
Acceleration = 5/5= 1 m/s^2 

Equation of motion,s=ut+(1/2)at^2 

u=18 km/h=5 m/s 
t=5 s 
a=1 m/s^2 
s= (5*5)+(1/2*1*5*5) 
s=25+12.5
 i.e.,
s=37.5 m 



Hope it helpful

Answer 3

Hello mate!!


Acceleration = Change in Velocity/Time 

Change in Velocity = 36-18 = 18 km/h=5 m/s 
Time= 5 Seconds 
Acceleration = 5/5= 1 m/s^2 

Equation of motion,s=ut+(1/2)at^2 

u=18 km/h=5 m/s 
t=5 s 
a=1 m/s^2 
s= (5*5)+(1/2*1*5*5) 
s=25+12.5
 i.e.,
s=37.5 m 



Hope it helpful