Physics, asked by samujjwalray, 11 months ago

)A car changes its velocity from 5 m/s to 45 m/s in 8 seconds.Calculate the acceleration of the car.

Answers

Answered by TheValkyrie
0

v=45m/s

u=5m/s

t=8s

a=(v-u)/t

a=(45-5)/8

a=5m/s^2

Answered by Anonymous
2

u = 5 m/s

v = 45 m/s

t = 8 s

According to first equation of motion

V = U + at

45 = 5 + 8a

50 = 8a

a = 50/8

Acceleration = a = 6.25m/s2

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