Question

a car comes to rest in 10seconds from 10m/s in covering a distance of 75metres. find the retardation provided by the breaks​

Answer 1

Answer:

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Explanation:

initial speed of the car u = 10 m / s Final

speed of the car V = 0 m / s Acceleration

( or retardation ) of the car a = 2 m/

sUSing v2 - u2 = 2aS • 0 -102 = ( - 2 )

ANSWER __S = 2 × 2100 = 25 m✨

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Answer 2

Answer:

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Explanation:

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