Question

a car comes to rest in 10seconds from 10m/s in covering a distance of 75metres. find the retardation provided by the breaks​

__ Princess all your questions are full hey please do your questions __​

Answer 1

Answer:

Initial speed of the car u=10 m/s

Final speed of the car v=0 m/s

Acceleration (or retardation) of the car a=−2 m/s

Using v

2

−u

2

=2aS

∴ 0−10

2

=2(−2)S

⟹ S=

2×2

100

=25 m

np dude l didn't feel bad

kk be happy n be smiling always☺️☺️☺️☺️

Explanation:

l hope it will help u ☺️☺️☺️☺️☺️

Answer 2

Answer:

now see profile I guess it's clear.