A car comes to rest when break was applied for 3s to get a retardation of 2m/s2. Calculate how far the car would have travelled after applying a break? pls answer fast....
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see it's given
t= 3 sec
v= 0 (since the car stops)
then we have a= -2ms-²
we need to find s!!
so v=u+at
so from here we get the value of u as 6 metres
and then we find s by using
s=ut+1/2at²
and we get s = 9 metresss!!
there you go!
hope it helps..
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