A car completes a journey of 630 km in 9 hours 30 minutes The first one- third of the journey is completed at 50/3m/sec Find the speed for the rest of the journey
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Answered by
8
Heyaaa!!!
50/3 m/s------> 60km/hr
1/3rd journey=630km/3
=210 Kms!
So with 60 km to cover distance 210 km.. time taken=210/60
=3.5 hr!
so total time=9.5 hr(9 hr 30 min)
Remaining time=9.5-3.5=6 hrs!
Hope it helps!
50/3 m/s------> 60km/hr
1/3rd journey=630km/3
=210 Kms!
So with 60 km to cover distance 210 km.. time taken=210/60
=3.5 hr!
so total time=9.5 hr(9 hr 30 min)
Remaining time=9.5-3.5=6 hrs!
Hope it helps!
alia49:
hi
Answered by
18
distance = 630km
1/3of630km=210km
(50/3)m/sec=50/3*18/5=60kmph
time taken to travel 210km =210/6=3.5hr
time left is 9.5 - 3.5=6hr
left over distance = 630-210=420km
speed when travelling 420km= speed=distance/time=420/6=70kmph
1/3of630km=210km
(50/3)m/sec=50/3*18/5=60kmph
time taken to travel 210km =210/6=3.5hr
time left is 9.5 - 3.5=6hr
left over distance = 630-210=420km
speed when travelling 420km= speed=distance/time=420/6=70kmph
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