A car completes its motion twice in a circular path of radius 7 m .The distance covered by the car is *
88 m
44m
22 m
11 m
Answers
Answered by
0
Answer:
The tangential acceleration is given by a
t
=5m/s
2
and the net acceleration a=7m/s
2
.
We know that tangential and radial acceleration are perpendicular to each other.
Thus, a
2
=a
r
2
+a
t
2
. Substituting the values of a
r
and a, we get a
r
=
49−25
=2
6
=4.89m/s
The radial acceleration is related to linear velocity as a
r
=v
2
/R. Thus, v=
a
r
R
=
4.89×100
=22m/s)
Answered by
0
Answer:
speed = distance traveled
time
half of the circumference
time
1/2 x 2 x π x r
2
1/2 x 2 x 22/7 x 7
2
11 ms¹
Speed and velocity can be equal for uniform motion along a straight line.
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