a car cover a distance of 3150km in 22hours 12min. if it cover 5/7 of its journey at a speed of 150km/h find the speed of the rest of the journey
Answers
Step-by-step explanation:
Car travelled 3150 km in 22 hours 12 min
on converting hours in min
(22+12)×60= 1332min
So we got that Car travelled 3150Km in 1332min
According to the question,
From his total journey which is 3150 Km car travelled 5/7of 3150km in the speed of 150Km/h.
5/7×3175=2250
So car travelled 2250Km out of 3150 Km in speed of 150Km/h.
If the car travelled 2250 Km in speed of 150Km/h then the time = 2250÷150=15h
We get that the car travelled 2250 Km in 15h
Now, 3150-2250=900 Km of journey is left
Question is find the speed of the rest of the journey
So speed = Distance travelled / Time taken
= 900/(22-15)
= 900/7
= 128.5Km/h(approx) is the
speed of the rest journey.
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Answer:
5/7 of its journey = 5/7 x 3150 = 2250 = km
Find the time taken for the first part of the journey:
Time = Distance - Speed
Time = 2250 = 150 = 15 hours
Find the time taken for the second part of the journey:
22 hours 12 min - 15 hours = 7 hours 12
=
mins = 7.2 hours
=