A car covered half the distance between two towns in 3hrs and 30mins. After that he increased his speed by 3km/hr. He covered the remaining half of the distance in 3hrs and 15mins. Find the distance between the two towns and the initial speed of the car.
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Let the distance between the town's be 2x and speed be y.
So x=2.5y
And x=7(y+2)/3 - 2hr 20min is 7/3 hr.
So equating 1 and 2 we have 7y+14 = 7.5y
Or y=28
So initial speed is 28
So x is 2.5y= 70
Which means distance is 2x or 140kms
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