A car covers 1/3 of its journey with a speed of 20 km/hr & remaining distance with speed 40 km/ hr.find avg speed of car
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20
Let the distance be X.
1 / 3 x he covers using 20 km / h
Remaining = 2 / 3 km which he covers using 40 km / h
Lets take the distance x to be 1 then :
Time for the first portion will be:
T = Distance / speed
1/3 × 1/20 = 1/60 hrs
Second portion:
2 / 3 × 1/40 = 1 / 60 hrs
Average speed = total distance / total time
Total time = 2 / 60 = 1 / 30 hrs
Average speed :
1 ÷ 1 / 30
1 × 30 = 30 km / h
1 / 3 x he covers using 20 km / h
Remaining = 2 / 3 km which he covers using 40 km / h
Lets take the distance x to be 1 then :
Time for the first portion will be:
T = Distance / speed
1/3 × 1/20 = 1/60 hrs
Second portion:
2 / 3 × 1/40 = 1 / 60 hrs
Average speed = total distance / total time
Total time = 2 / 60 = 1 / 30 hrs
Average speed :
1 ÷ 1 / 30
1 × 30 = 30 km / h
Answered by
7
Answer:
Explanation:
Let the distance be X.
1 / 3 x he covers using 20 km / h
Remaining = 2 / 3 km which he covers using 40 km / h
Lets take the distance x to be 1 then :
Time for the first portion will be:
T = Distance / speed
1/3 × 1/20 = 1/60 hrs
Second portion:
2 / 3 × 1/40 = 1 / 60 hrs
Average speed = total distance / total time
Total time = 2 / 60 = 1 / 30 hrs
Average speed :
1 ÷ 1 / 30
1 × 30 = 30 km / h
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