A car covers a certain distance in 10 hours. If it covers half distance at 40 km/hr and
remaining distance at 60 km/hr, what distance did the car cover?
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Letx consider, x= total distance covered by the car,
Time taken to complete the half distance with velocity v=40km/h,
t1=2×40x=80xhr. . . . .(1)
The time taken to complete another half distance with velocity u=60km/h
t2=2×60x=120xhr
The total time taken, t=t1+t2
t=80x+120x=48xhr
The average speed of the car,
vavg=x/48x=48km/h
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