Question

a car covers a distance d1 with a speed v1, next distance d2 in a time t1 and finally time t2 with a speed v2.find the average speed

Answer 1

Explanation:

third distance = speed×time

= v2t2

time taken in first distance = distance/speed

= d1/v1

average speed = total distance traveled/total time taken

= d1+d2+v2t2 / d1v1+t1+t2

Answer 2

Answer:

The average speed of the car is $\frac{d_1+d_2}{t_1+t_2}$.

Explanation:

The following formula yields the average speed:

$V_a_v_g=\frac{D}{T}$        (1)

Where,

$V_a_v_g$=average speed of the body

D=total distance

T=total time taken

Now total distance i.e.D is calculated as,

$D=d_1+d_2$     (2)

And the total time i.e.T is calculated as,

$T=t_1+t_2$     (3)

When we enter the entities into equation (1), we obtain;

$V_a_v_g=\frac{d_1+d_2}{t_1+t_2}$

Hence, the average speed of the car is $\frac{d_1+d_2}{t_1+t_2}$.

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